The size of the species $I, I^{-}$ & $I^{+}$ follows the order:

I > I^{-} > I^{+}

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I^{+} > I > I^{-}

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I^{-} > I > I^{+}

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I^{+} > I^{-} > I

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Solution

The correct option is C $I^{-} > I > I^{+}$
If we have an element X and the species $X^{+}$ and $X^{-}$ , the trend in size generally followed is: $X^{-} > X > X^{+}$ .

This is because the anion will have an extra electron to accomodate making the size of the ion to be bigger than the neutral atom. On the other hand, the cation is generally smaller due to the increase in the effective nuclear charge.

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The size of species $I$ , $I^{\oplus}$ and $I^{⊖}$ decreases in the order

Which of the following is the correct order of size of the given species
(a) $I > I^{-} > I^{+}$ (b) $I^{+} > I^{-} I$ (c) $I > I^{+} > I^{-}$ (d) $I^{-} > I > I^{+}$

Q. The size of the species

I, I^{-}

I^{+}

follows the order:

The size of species $I$ , $I^{\oplus}$ and $I^{⊖}$ decreases in the order

Q. For the species

(I^{-}, C l^{-}, B r^{-})

, the increasing order of nucleophilicity in water would be:

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The size of the species I,I− & I+ follows the order:

The size of the species $I, I^{-}$ & $I^{+}$ follows the order: