The slope and intercept respectively of the graph drawn between logxm and log P in respect of the logarithmic form of Freundlich adsorption isotherm are -

The correct option is B 1n, log K The equation of freundlich adsorption isotherm is #160; logxm=logK+1nlogP .According to the equation slope is ...

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Standard XII

Chemistry

Fruendlich Isotherm

The slope and...

Question

The slope and intercept respectively of the graph drawn between $l o g \frac{x}{m}$ and log P in respect of the logarithmic form of Freundlich adsorption isotherm are :

n . l o g \frac{1}{K}

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\frac{1}{n}, l o g K

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l o g n, \frac{1}{K}

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n, l o g K

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Solution

The correct option is B $\frac{1}{n}, l o g K$

The equation of freundlich adsorption isotherm is $l o g \frac{x}{m} = l o g K + \frac{1}{n} l o g P$ .
According to the equation slope is $\frac{1}{n}$ and intercept is $l o g K$ .
Hence, option B is correct.

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Similar questions

Q. In the Freundlich's adsorption isotherm equation,

log \frac{x}{m} = log K + (\frac{1}{n}) log p

, the value of

n

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For a linear plot of log $(\frac{x}{m})$ versus log p in a Freundlich adsorption isotherm, which of the following statements is correct? (k and n are constants)

Q. In the Freundlich adsorption isotherm, log

(\frac{x}{m}) = l o g k + \frac{1}{n} l o g p,

the value of n is

Q. For a linear plot of log(x/m) versus log P in a Freundlich adsorption isotherm which of the following statement is correct?

Q. For a linear plot of

l o g (x / m)

versus

l o g P

in a Freundlich adsorption isotherm, which of the following statements is correct? (k and n are constants)

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The slope and intercept respectively of the graph drawn between logxm and log P in respect of the logarithmic form of Freundlich adsorption isotherm are :

The correct option is B 1n,logKThe equation of freundlich adsorption isotherm is logxm=logK+1nlogP.According to the equation slope is 1n and intercept is logK. Hence, option B is correct.

The slope and intercept respectively of the graph drawn between $l o g \frac{x}{m}$ and log P in respect of the logarithmic form of Freundlich adsorption isotherm are :

The correct option is B $\frac{1}{n}, l o g K$

The equation of freundlich adsorption isotherm is $l o g \frac{x}{m} = l o g K + \frac{1}{n} l o g P$ .
According to the equation slope is $\frac{1}{n}$ and intercept is $l o g K$ .
Hence, option B is correct.