The slope and y-intercept of the following line are respectively
$8 x - 4 y - 1 = 0$

s l o p e = m = \frac{- 1}{2} a n d y - i n t e r c e p t = \frac{1}{4} .

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s l o p e = m = 2 a n d y - i n t e r c e p t = - \frac{1}{4} .

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s l o p e = m = - \frac{1}{2} a n d y - i n t e r c e p t = - \frac{1}{4} .

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s l o p e = m = \frac{1}{2} a n d y - i n t e r c e p t = \frac{1}{4} .

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Solution

The correct option is B $s l o p e = m = 2 a n d y - i n t e r c e p t = - \frac{1}{4} .$
Given line
$8 x - 4 y - 1 = 0$
Comparing above eq with $y = m x + c$ where m is slope and c is y intercept
Here $m = 2, c = - \frac{1}{4}$

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The slope intercept form of the line 2x+2y=7 and the value of slope and y intercept are

Find the slope (m) and y - intercept (c) of the line $y = 4 x - \frac{1}{2}$ .

= \frac{- 2}{3}

= \frac{1}{2}

x + y - 1 = 0

y -

\frac{x}{2} + \frac{y}{4} = 1

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