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Determining Acceleration from Velocity-Time Graph

The slope of ...

Question

The slope of a displacement time graph is avg velocity, then slope of velocity time graph is ??

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Solution

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$N o t e : t h e s l o p e o f d i s p l a c e m e n t o r p o s i t i o n t i m e g r a p h a t a n t t i m e i s n o t t h e a v e r a g e v e l o c i t y b u t i t i s t h e i n s \tan \tan e o u s v e l o c i t y F o r m u l a o f a c c e l e r a t i o n i s a = \frac{d v}{d t} S o T h e s l o p e o f v e l o c i t y t i m e g r a p h i s i n s \tan \tan e o u s a c c e l e r a t i o n . R e g a r d s$

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Q. The slope of the velocity - time graph provides displacement.

Q. Slope of velocity time graph gives about displacement or distance

Q. In a displacement - time graph, slope gives velocity.

Q. Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.

Column-I	Column-II
(a)	Velocity-time graph	(p)	Slope $\to$ negative
(b)	Acceleration-time graph	(q)	Slope $\to$ positive
(c)	Displacement-time graph	(r)	Slope $\to$ zero
		(s)	$\| S l o p e \| \to$ increasing
		(t)	$\| S l o p e \| \to$ decreasing
		(u)	$\| S l o p e \| \to$ constant

Q. Displacement-time graph of a body moving with uniform velocity is always a straight line with slope =

0

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Determining Acceleration from Velocity-Time Graph

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