The slope of a line which makes an angle of ${60}^{\circ }$ with the positive direction of y – axis is

The correct option is A $\frac{1}{\sqrt{3}}$

We know that the slope of line is given by $\tan \theta$ where $\theta$ is the angle between the line and the x- axis.

Since, x- axis and y-axis are perpendicular and the angle made by the line with y- axis is ${60}^{\circ }$, therefore, angle made by the x- axis is,

$\Rightarrow \theta ={90}^{\circ }-{60}^{\circ }={30}^{\circ }$

Thus, Slope of the line $=\tan {30}^{\circ }=\frac{1}{\sqrt{3}}$