The slope of plate characteristic and mutual characteristic curves of a triode value is 0.02 mA/V and 1 mA/V. The amplification factor of triode value is:

2 \times 10^{8}

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Solution

The correct option is C 50
$η = amplification factor = \frac{S / mututud chat}{S / plate cha}$
$= \frac{1 m A / V}{0.02 m A / V}$
$= \frac{100}{0.02} = 50$

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The slope of plate characteristic and mutual characteristic curves of a triode value is 0.02 mA/V and 1 mA/V. The amplification factor of triode value is:

The correct option is C 50η=amplification factor=S/mututud chatS/plate cha=1mA/V0.02mA/V=1000.02=50

The correct option is C 50
$η = amplification factor = \frac{S / mututud chat}{S / plate cha}$
$= \frac{1 m A / V}{0.02 m A / V}$
$= \frac{100}{0.02} = 50$