Question

The smallest ketone and its next homologue are reacted with NH2OH to form oxime. What will be the result?

• A. Two different oximes are formed
• B. Three different oximes are formed
• C. Two oximes are optically active
• D. All oximes are optically active

Answer 1

Correct option: (C)

Ketones are carbonyl compounds and react with $N{H}_{2}OH$ to form oxime with the loss of water molecules.

The smallest ketone is Propanone (acetone) having the molecular formula $C_3{H}_{6}O$

The next homologue of Propanone is butanone having the molecular formula $C_4{H}_{8}O$

Reaction of Propanone with $N{H}_{2}OH$:

Propanone reacts with $N{H}_{2}OH$, acetoxime will be formed with by the elimination of water molecule.

Reaction of butanone with $N{H}_{2}OH$:

Butanone reacts with $N{H}_{2}OH$, an oxime will be formed with the elimination of the water molecule.

The oxime B will have two isomer which are shown below:

Hence, the correct option is (C).