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Introduction to Le Chatelier's Principle

The solubilit...

Question

The solubility of a solute in water varies with temperature as given by $: S = A e^{\frac{- Δ H}{R T}}, Δ H$ being the enthalpy of solution. For a given solute, variation of In S with temperature is as shown in the figure. The solute is expected to be ?

$C a O$

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$C u S O_{4}$

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$M g S O_{4}$

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$C u S O_{4} .5 H_{2} O$

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Solution

The correct option is D
$C u S O_{4} .5 H_{2} O$

ln $S = l n A - \frac{Δ H}{R} \times \frac{1}{T}$
The slope of the graph is negative. So $Δ H > 0.$ Hence, dissolution is endothermic. Hydrated salt dissolves endothermically.

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