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Byju's Answer
Standard XII
Chemistry
Solubility Product
The solubilit...
Question
The solubility of aluminium sulphate is
1.0
×
10
−
4
m
o
l
/
l
i
t
, the solubility product is :
A
108
×
10
−
4
m
o
l
/
l
i
t
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B
10800
×
10
−
20
m
o
l
/
l
i
t
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C
1080
×
10
−
18
m
o
l
/
l
i
t
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D
1.08
×
10
−
18
m
o
l
/
l
i
t
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Solution
The correct option is
D
1.08
×
10
−
18
m
o
l
/
l
i
t
A
l
2
(
S
O
4
)
3
⇋
2
A
l
3
+
+
3
S
O
2
−
4
K
s
p
=
(
2
S
)
2
(
3
S
)
3
=
108
×
S
5
K
s
p
=
1.08
×
10
−
18
m
o
l
/
l
i
t
Option D is correct.
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Similar questions
Q.
(
K
s
p
)
AgCl is
2.8
×
10
−
10
at
25
∘
C. Calculate solubility of AgCl in
0.1
(
M
)
A
g
N
O
3
Q.
K
s
p
o
f
A
g
C
l
is
=
2.8
×
10
−
10
at
25
∘
C. Calculate solubility of AgCl in 0.1 (M) NaCl
Q.
The solubility product of NaCl is
2.5
×
10
−
9
m
o
l
e
s
2
/
l
i
t
2
. Its solubility is:
Q.
S
O
2
reacts with
O
2
as follows
2
S
O
2
+
O
2
→
2
S
O
3
the rate of disappearance of
S
O
2
is
2.4
×
10
−
4
m
o
l
l
i
t
−
1
m
i
n
−
1
Then:
Q.
Solubility of
M
X
2
type electrolytes is
0.5
×
10
−
4
mole/lit. Then find out
K
s
p
of electrolytes.
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