Question

The solubility of anhydrous $AlC{l}_3$ and hydrous $AlC{l}_3$ in diethyl ether are $S_1$ and $S_2$ respectively. Then -

• A. $S_1=S_2$
• B. $S_1>S_2$
• C. $S_1<S_2$
• D. $S_1<S_2$ but not $S_1=S_2$

Answer 1

The correct option is B $S_1>S_2$

Anhydrous AlCl3 will dissolve the diethyl ether because anhydrous ​AlCl3 is a good lewis acid. It is electron deficient. The lone pairs of diethyl ether will be donated to the anhydrous ​AlCl3 due to which it is soluble. On the other hand, hydrous ​AlCl3 have the water molecules which make it poor lewis acid.

So, $S_1>S_2$.