Question

The solubility of potassium chloride at ${20}^{\circ }C$ is 34.7 g in 100 g of water. The density of the solution is 1.3 g $m{L}^1$. What is the w/V percentage of potassium chloride in the solution ?

• A. 25.76
• B. 32.98
• C. 33.49
• D. 22.56

Answer 1

The correct option is C 33.49

let volume of the solution be v.
density=$\frac{(34.7+100)}{v}=1.3$.

which is therefore 134.7=1.3v

v= $\frac{134.7}{1.3ml}$.

%w/v=mass of KCl in 100 ml of solution.
$\frac{134.7}{1.3}$ ml contains 34.7 g of KCl.

100 ml contains:(100 x 34.7 x 1.3)/134.7 = 33.49%