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Question

The solution for the differential equation dyy+dxx=0 is:

A
1y+1x=c
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B
logx.logy=c
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C
xy=C
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D
x+y=c
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Solution

The correct option is C xy=C
We have, dyy+dxx=0
Integrate both sides,
(dyy+dxx)=0
dyy+dxx=c
, since differentiation any constant is 0
lnx+lny=c, use basic formula
ln(xy)=c, product rule of logarithm loga+logb=log(ab)
xy=ec=C

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