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Byju's Answer
Standard XII
Mathematics
Homogeneous Differential Equation
The solution ...
Question
The solution for the differential equation
d
y
y
+
d
x
x
=
0
is:
A
1
y
+
1
x
=
c
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B
log
x
.
log
y
=
c
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C
x
y
=
C
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D
x
+
y
=
c
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Solution
The correct option is
C
x
y
=
C
We have,
d
y
y
+
d
x
x
=
0
Integrate both sides,
∫
(
d
y
y
+
d
x
x
)
=
∫
0
⇒
∫
d
y
y
+
∫
d
x
x
=
c
, since differentiation any constant is 0
⇒
ln
x
+
ln
y
=
c
, use basic formula
⇒
ln
(
x
y
)
=
c
, product rule of logarithm
log
a
+
log
b
=
log
(
a
b
)
⇒
x
y
=
e
c
=
C
Suggest Corrections
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