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Introduction and Degree of Hydrolysis

The solution ...

Question

The solution of a salt of a weak acid and weak base will have $p H$ -

( $K_{b}$ = $10^{- 6}$ ; $K_{a}$ = $10^{- 4}$ )

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Solution

The correct option is C
6

$p H$ = $7 + \frac{1}{2} p K_{a} - \frac{1}{2} p K_{b}$

= $7 + 2 - 3$ = $6$

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Similar questions

(K_{a} = 2 \times 10^{- 6})

(K_{b} = 5 \times 10^{- 7})

p H

% α

(B A)

0.1 M

K_{a}

H A = 10^{- 6}

K_{b}

B O H = 10^{- 6}

K_{b}

H N O_{3}

N H_{4} C N

(K_{a} = 6.2 \times 10^{- 10})

N H_{4} O H (K_{b} = 1.8 \times 10^{- 5})

N H_{4} C N

25^{\circ} C

K_{a}

K_{b}

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