The solution of 3x-1-5-1-x-2-3-x-1-2 is

The correct option is B 7 3x 1/5 1+x/2+x 1/2=3 6x 2 5 5x+5x 5/10=3 6x 12/10=3 6x = 42x = 7 ...

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Byju's Answer

Standard VIII

Mathematics

Solving Equations with Variables on Both Sides

The solution ...

Question

The solution of $\frac{3 x - 1}{5} - \frac{1 + x}{2} = 3 - \frac{x - 1}{2}$ is

5

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7

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Solution

The correct option is B $7$
$\frac{3 x - 1}{5} - \frac{1 + x}{2} + \frac{x - 1}{2} = 3$
$\frac{6 x - 2 - 5 - 5 x + 5 x - 5}{10} = 3$
$\frac{6 x - 12}{10} = 3$
6x = 42
x = 7

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Similar questions

Q. Select the expression you will get for x and y if you solve the following equations using the cross multiplication method.

\sqrt{3} x = 2

\frac{x}{3} = 7 - \frac{y}{5}

Q. Find

x

\frac{x + 7}{3} = 1 + \frac{3 x - 2}{5}

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Solve :

\frac{x + 7}{3} = 1 + \frac{3 x - 2}{5}

Solve for x :-

\frac{x + 7}{3} = 1 + \frac{3 x - 2}{5}

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The solution of 3x−15−1+x2=3−x−12 is

The correct option is B 73x−15−1+x2+x−12=36x−2−5−5x+5x−510=36x−1210=36x = 42x = 7

The solution of $\frac{3 x - 1}{5} - \frac{1 + x}{2} = 3 - \frac{x - 1}{2}$ is

The correct option is B $7$
$\frac{3 x - 1}{5} - \frac{1 + x}{2} + \frac{x - 1}{2} = 3$
$\frac{6 x - 2 - 5 - 5 x + 5 x - 5}{10} = 3$
$\frac{6 x - 12}{10} = 3$
6x = 42
x = 7