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Question

The solution of the differential equation d2ydx2=sin3x+ex+x2 when y1(0)=1 and y(0)=0 is

A
sin3x9+ex+x412+13x1
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B
sin3x9+ex+x412+13x
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C
cos3x3+ex+x412+13x+1
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D
none of these
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Solution

The correct option is A sin3x9+ex+x412+13x1
Integrating the given differential equation, we have
dydx=cos3x3+ex+x33+C1
but y1(0)=1 so 1=(1/3)+1+C1C1=1/3.
Again integrating, we get
y=sin3x9+ex+x412+13x+C2
but y(0)=0 so 0=0+1+C2C2=1.Thus
y=sin3x9+ex+x412+13x1

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