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Question

The solution of the differential equation dydx−2y tan 2x=e2xsec 2x is


A

y sin 2x=e2x+c

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B

2y cos 2x=e2x+c

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C

y=e2x cos2x+c

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D

y cos 2x+e2x=c

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Solution

The correct option is B

2y cos 2x=e2x+c


Given equation is an L.D.E in y

P = -2 tan 2x

Integrating factor = cos 2x

General Solution is 2y cos 2x=e2x+c


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