The solution of the differential equation dydx−2y tan 2x=e2xsec 2x is
y sin 2x=e2x+c
2y cos 2x=e2x+c
y=e2x cos2x+c
y cos 2x+e2x=c
Given equation is an L.D.E in y
P = -2 tan 2x
Integrating factor = cos 2x
General Solution is 2y cos 2x=e2x+c