wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The solution of the differential equation xdx+ydy=x2ydyy2xdx is

A
x21=C(1+y2)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+1=C(1y2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x31=C(1+y3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x3+1=C(1y3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Join BYJU'S Learning Program
CrossIcon