Question

The Solution of the following pairs of simultaneous equation is $\frac{2x-1}{3}+\frac{y+2}{4}=4$ & $\frac{x+3}{2}-\frac{x-y}{3}=3$

• A. x = -5, y = - 4
• B. x = 5, y = 2
• C. x = -5, y = 2
• D. x = 5, y = 4

Answer 1

The correct option is B x = 5, y = 2

On simplifying $\frac{2x-1}{3}+\frac{y+2}{4}=4$, we get $8x+3y=46$ ---- (1)
And on simplifying, $\frac{x+3}{2}+\frac{x-y}{3}=3$, we get $x+2y=9$ ---- (2)

Multiplying equation $\left(2\right)$ with $8$ we get, $8x+16y=72$ ----- equation $\left(3\right)$

Subtracting equation $\left(1\right)$ from $\left(3\right)$, we get $13y=26=>y=2$

Substituting $y=2$ in the equation $\left(2\right)$, we get $x+2y=9=>x=5$