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Question

# The Solution of the following pairs of simultaneous equation is 2x−13+y+24=4 & x+32−x−y3=3

A
x = -5, y = - 4
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B
x = 5, y = 2
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C
x = -5, y = 2
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D
x = 5, y = 4
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Solution

## The correct option is B x = 5, y = 2On simplifying 2x−13+y+24=4, we get 8x+3y=46 ---- (1)And on simplifying, x+32+x−y3=3, we get x+2y=9 ---- (2)Multiplying equation (2) with 8 we get, 8x+16y=72 ----- equation (3)Subtracting equation (1) from (3), we get 13y=26=>y=2 Substituting y=2 in the equation (2), we get x+2y=9=>x=5

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