CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The Solution of the following pairs of simultaneous equation is 2x13+y+24=4 & x+32xy3=3

A
x = -5, y = - 4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x = 5, y = 2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x = -5, y = 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x = 5, y = 4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B x = 5, y = 2
On simplifying 2x13+y+24=4, we get 8x+3y=46 ---- (1)
And on simplifying, x+32+xy3=3, we get x+2y=9 ---- (2)

Multiplying equation (2) with 8 we get, 8x+16y=72 ----- equation (3)

Subtracting equation (1) from (3), we get 13y=26=>y=2

Substituting y=2 in the equation (2), we get x+2y=9=>x=5


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Multiplication under Integers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon