The solution of the pair of simultaneous equations
$3 x + 4 y = - 6$
$4 x + 3 y = - 1$

x = + 3

and

y = - 2

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x = + 2

and

y = - 3

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x = - 3

and

y = + 2

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x = - 2

and

y = - 3

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Solution

The correct option is B $x = + 2$ and $y = - 3$
$3 x + 4 y = - 6 => 3 x = - 6 - 4 y => x = \frac{- 6 - 4 y}{3} 4 x + 3 y = - 1 => 4 (\frac{- 6 - 4 y}{3}) + 3 y = - 1 => - 24 - 16 y + 9 y = - 3 => - 7 y = 21 => y = - 3 x = \frac{- 6 - 4 \times (- 3)}{3} = 2$
$x = + 2$ and $y = - 3$

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