The solution set of the equation $x^{2 / 3} + x^{1 / 3} - 2 = 0$ is

{8, 1}

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{8, - 1}

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{- 8, - 1}

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{- 8, 1}

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Solution

The correct option is D ${- 8, 1}$
Put $x^{1 / 3} = t$

$t^{2} + t - 2 = 0$

$(t + 2) (t - 1) = 0$

$t = 1, t = - 2$

$x^{\frac{1}{3}} = 1, x^{1 / 3} = - 2$

$x = 1, x = - 8$ .

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