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Inequalities Involving Modulus Function

The solution ...

Question

The solution set of $x^{2} - 7 x + 12 \geq 0$ is

A

[3, 4]

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B

(3, 4)

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C

(- \infty, 3) \cup (4, \infty)

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D

(- \infty, 3] \cup [4, \infty)

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Solution

The correct option is D $(- \infty, 3] \cup [4, \infty)$
$x^{2} - 7 x + 12 \geq 0 \Rightarrow (x - 3) (x - 4) \geq 0$

$∴ x \in (- \infty, 3] \cup [4, \infty)$

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Inequalities Involving Modulus Function

Standard XI Mathematics

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