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Question

The solution to the differential equation ylny+xy=0, where y(1)=e, is

A
|xlny|=1
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B
xy(lny)=1
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C
(lny)2=2
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D
lny+(x22)y=1
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Solution

The correct option is A |xlny|=1
xdydx+y(lny)=0
dxx+dyy(lny)=0
ln|x|+ln|(lny)|=ln|c|
|xlny|=|c|
y(1)=ec=±1
Hence, the equation of the curve is |xlny|=1

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