The solution to the differential equation ylny+xy′=0, where y(1)=e, is
A
|xlny|=1
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B
xy(lny)=1
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C
(lny)2=2
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D
lny+(x22)y=1
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Solution
The correct option is A|xlny|=1 xdydx+y(lny)=0 ⇒∫dxx+∫dyy(lny)=0 ⇒ln|x|+ln|(lny)|=ln|c| ⇒|xlny|=|c| y(1)=e⇒c=±1
Hence, the equation of the curve is |xlny|=1