The sound intensity is $0.008 W / m^{2}$ at a distance of 10 m from an isotropic point source of sound. The power of the source is nearly :

2.5 watt

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0.8 watt

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8 watt

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10 watt

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Solution

The correct option is D 10 watt
Given, $I = 0.008 W / m^{2}$

Surface Area of the sphere having a radius of 1 m is
$A = 4 π r^{2} = 4 π 10^{2} = 400 π$

The power of the source is
$P = I A = 0.008 \times 400 \times π = 3.2 \times \frac{22}{7} = 10.05 W$

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The sound intensity is 0.008W/m2 at a distance of 10 m from an isotropic point source of sound. The power of the source is nearly :

The correct option is D 10 wattGiven, I=0.008W/m2Surface Area of the sphere having a radius of 1 m is A=4πr2=4π102=400πThe power of the source is P=IA=0.008×400×π=3.2×227=10.05W

The sound intensity is $0.008 W / m^{2}$ at a distance of 10 m from an isotropic point source of sound. The power of the source is nearly :

The correct option is D 10 watt
Given, $I = 0.008 W / m^{2}$

Surface Area of the sphere having a radius of 1 m is
$A = 4 π r^{2} = 4 π 10^{2} = 400 π$

The power of the source is
$P = I A = 0.008 \times 400 \times π = 3.2 \times \frac{22}{7} = 10.05 W$