Question

The specific conductance of a 0.1N KCl solution is $0.012{ohm}^{-1}{cm}^{-1}$. The resistance of the cell containing the same solution is $55ohms$. Then the cell constant is :

• A. $0.918{cm}^{-1}$
• B. $0.66{cm}^{-1}$
• C. $1.142{cm}^{-1}$
• D. $1.12{cm}^{-1}$

Answer 1

The correct option is B $0.66{cm}^{-1}$

$K=0.012{ohm}^{-1}{cm}^{-1}$

$P=55ohm$

$G=1/55n^{-1}$

$K=K\times G$ $K$ is cell constant

$0.012=K\times \frac{1}{55}$

$K=0.66{cm}^{-1}$