The specific conductance of a 0-20 molL -1 solution of an electrolyte at 200 C is 2-48 - 10-4 ohm -1 cm -1- The molar conductivity of the solution is -A- 1-24 ohm -1 cm 2 mol -1B- 4-96 ohm -1 cm 2 mol -1C- 0-24 ohm -1 cm 2 mol -1D- 0-49 ohm -1 cm 2 mol -1

The correct option is A 1.24 ohm^ 1 cm^2 mol^ 1 nbsp;λ _m=K×1000/M⇒2.48× 10^ 4×1000/0.20=1.24 ohm^ 1cm^2mol^ 1 nbsp; ...

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Byju's Answer

Standard XII

Chemistry

Equivalent, Molar Conductivity and Cell Constant

The specific ...

Question

The specific conductance of a $0.20 m o l L^{- 1}$
solution of an electrolyte at $20^{0} C i s 2.48 \times 10^{- 4} o h m^{- 1} c m^{- 1}$ . The molar conductivity of the solution is :

1.24 o h m^{- 1} c m^{2} m o l^{- 1}

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4.96 o h m^{- 1} c m^{2} m o l^{- 1}

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0.24 o h m^{- 1} c m^{2} m o l^{- 1}

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0.49 o h m^{- 1} c m^{2} m o l^{- 1}

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Solution

The correct option is A $1.24 o h m^{- 1} c m^{2} m o l^{- 1}$

Given that,
Specific conductance of a solution(k) = $2.48 \times 10^{- 4} O h m^{- 1} c m^{- 1}$
Concentration(Molarity) of a solution = 0.2 $m o l L^{- 1}$
Now, Using the Molar Conductivity formula = (1000 × k) / M

$λ_{m} = \frac{K \times 1000}{M} \Rightarrow \frac{2.48 \times 10^{- 4} \times 1000}{0.20} = 1.24 o h m^{- 1} c m^{2} m o l^{- 1}$
$∴$ Molar conductivity of solution = 1.24 $O h m^{- 1} c m^{2} m o l^{- 1}$

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The specific conductance of a 0.20 molL−1 solution of an electrolyte at 200C is 2.48×10−4ohm−1cm−1. The molar conductivity of the solution is :

The specific conductance of a $0.20 m o l L^{- 1}$
solution of an electrolyte at $20^{0} C i s 2.48 \times 10^{- 4} o h m^{- 1} c m^{- 1}$ . The molar conductivity of the solution is :