Question

The specific conductance of a $N/10KCI$ at ${25}^{0}C$ is $0.0112{ohm}^{-1}{cm}^{-1}$. The resistance of cell containing solution at the same temperature was found to be $55ohms$ . The cell constant will be:

• A. $6.16{cm}^{-1}$
• B. $0.616{cm}^{-1}$
• C. $0.0616{cm}^{-1}$
• D. $616{cm}^{-1}$

Answer 1

Answer: (A)

$6.16{cm}^{-1}$

$K=0.0112{ohm}^{-1}{cm}^{-1}$

$R=55r$

$G=1/55$

$K=K\times G$ ($K$ is cell constant)

$0.0112=K\times \frac{1}{55}$

$K=0.616{cm}^{-1}$