Question

The specific conductance of a N/10 KCl at ${25}^o$C is $0.0112$ ohm${}^{-1}$ cm${}^{-1}$. The resistance of cell-containing solution at the same temperature was found to be $55$ ohm. The cell constant will be:

• A. 6.16 cm${}^{-1}$
• B. 0.616 cm ${}^{-1}$
• C. 0.0616 cm${}^{-1}$
• D. 616 cm ${}^{-1}$

Answer 1

The correct option is B 0.616 cm ${}^{-1}$

We know that

specific conductance $=$ Cell constant $\times$ conductance

$⟹$ Cell constant $=$ Resistance $\times$ specific conductance

$G^{\ast }=55\times 0.0112=0.616$ cm${}^{-1}$

Hence, the correct option is $\text{B}$.