Question

The specific conductance of a N$/10$ KCl at ${25}^o$C is $0.0112$ $oh{m}^{-1}$ $c{m}^{-1}$. The resistance of cell containing at the same temperature was found to be $55$ ohms. The cell constant will be:

• A. $6.16c{m}^{-1}$
• B. $0.616c{m}^{-1}$
• C. $0.0616c{m}^{-1}$
• D. $616c{m}^{-1}$

Answer 1

The correct option is B $0.616c{m}^{-1}$

$CellConstant{G}^{\ast }=SpecificConductance\times R$

given

$R=55ohms$

$K=0.0112oh{m}^{-1}c{m}^{-1}$

$G^{\ast }=0.0112\times 55$

$=0.616c{m}^{-1}$