Question

The specific conductivity of $0.1$ $N$ $KCl$ solution at ${20}^0$C is $0.0212$ $oh{m}^{-1}c{m}^{-1}$. The solution was found to offer resistance of $55$ ohms. Find the cell constant of the conductivity cell.

• A. $2.25$
• B. $1.166$
• C. $1.936$
• D. none of these

Answer 1

The correct option is B $1.166$

Specific conductance $K=0.0212{\Omega }^{-1}c{m}^{-1}$

Normality = $0.1N$, Resistance = $55\Omega$

Cell constant $G^{\ast }$ = conductivity $\times$ Resistance

$G^{\ast }=K\times R$

$=0.0212\times 55$

$=1.166c{m}^{-1}$

Option B