Question

The specific conductivity of $N/10$ $KCl$ solution at ${20}^{o}C$ is $0.0212$ $oh{m}^{-1}$ $c{m}^{-1}$ and the resistance of the cell containing this solution at ${20}^o$C is $55$ ohm. The cell constant is:

• A. $3.324$ $c{m}^{-1}$
• B. $1.166$ $c{m}^{-1}$
• C. $2.372$ $c{m}^{-1}$
• D. $3.682$ $c{m}^{-1}$

Answer 1

Answer: (B)

$1.166$ $c{m}^{-1}$

The cell constant is of a particular cell and is determined as the ratio of the distance between the electrodes of the cell to the area of the electrodes.

Cell constant $K=\frac{l}{A}$

We know a relation,

$\kappa =C\times \frac{l}{A}$

$\frac{l}{A}=\kappa \times \frac{1}{C}=\kappa \times R=0.0212\times 55=1.66c{m}^{-1}$

Hence, the correct answer is option $\text{B}$.