Question

The specific conductance of $\frac{N}{10}KCl$ solution at ${20}^{\circ }C$ is $0.0212oh{m}^{-1}c{m}^{-1}$ and the resistance of cell containing this solution at ${20}^{\circ }C$ is 55 ohm. The cell constant is

• A. 1.166 cm^-1
• B. 2.173 cm^-1
• C. 3.324 cm^-1
• D. 4.616 cm^-1

Answer 1

The correct option is A 1.166 cm^-1

$K=\frac{1}{R}\times cellconstant$
Cell constant $=K\times R=0.0212\times 55=1.166c{m}^{-1}$