Question

The specific conductivity of $N/10KCl$ solution at ${20}^{o}C$ is $0.0212{ohm}^{-1}{cm}^{-1}$ and the resistance of the cell containing this solution at ${20}^{o}C$ is $55ohm$. The cell constant is:

• A. $4.616{cm}^{-1}$
• B. $1.166{cm}^{-1}$
• C. $2.173{cm}^{-1}$
• D. $3.324{cm}^{-1}$

Answer 1

The correct option is B $1.166{cm}^{-1}$

$K=0.0212{ohm}^{-1}{cm}^{-1}R=55ohmG=\frac{1}{R}$

$K=K\times G$ where K = cell constant

$0.0212=K\times \frac{1}{55}$

$K=1.166{cm}^{-1}$