The specific heat capacity of a metal is 0-01 cal-g-C- If heat capacity of m kg of metal is 0-42 J-C- Find the value of m-

Specific heat capacity (c)=0.01 cal/g^∘C Heat capacity (C)=0.42 J/^∘C nbsp; We know; Specific heat capacity (c)=0.01 cal/g^∘C=0.01× 4.210^ 3 J/kg^∘C =42 J/kg^ ...

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Standard XIII

Physics

Specific Heat Capacity

The specific ...

Question

The specific heat capacity of a metal is $0.01 {cal/g}^{\circ} C$ . If heat capacity of $m kg$ of metal is $0.42 J /^{\circ} C$ . Find the value of $m$ .

10^{- 2}

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Solution

The correct option is A $10^{- 2}$
Specific heat capacity $(c) = 0.01 {cal/g}^{\circ} C$
Heat capacity $(C) = 0.42 J /^{\circ} C$
We know;
Specific heat capacity $(c) = 0.01 {cal/g}^{\circ} C = \frac{0.01 \times 4.2}{10^{- 3}} {J/kg}^{\circ} C$
$= 42 {J/kg}^{\circ} C$
Also,
Heat capacity $(C) = m \times 42 {J/kg}^{\circ} C \Rightarrow 0.42 {J/}^{\circ} C = m \times 42 {J/kg}^{\circ} C$
$\Rightarrow m = 10^{- 2} kg$

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Specific Heat Capacity

Standard XIII Physics

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The specific heat capacity of a metal is 0.01 cal/g∘C. If heat capacity of m kg of metal is 0.42 J/∘C. Find the value of m.

The correct option is A 10−2Specific heat capacity (c)=0.01 cal/g∘C Heat capacity (C)=0.42 J/∘C We know; Specific heat capacity (c)=0.01 cal/g∘C=0.01×4.210−3 J/kg∘C =42 J/kg∘C Also, Heat capacity (C)=m×42 J/kg∘C⇒0.42 J/∘C=m×42 J/kg∘C ⇒m=10−2 kg

The specific heat capacity of a metal is $0.01 {cal/g}^{\circ} C$ . If heat capacity of $m kg$ of metal is $0.42 J /^{\circ} C$ . Find the value of $m$ .