The specific heat capacity of water is 4200 J-kg - C- Calculate the heat capacity of 10 kg of water per - C-

The correct option is C 42 kJHeat Capacity =Specific heat× mass =4200J/Kg^oC × 10 =42000J =42kJ ...

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Standard X

Physics

Effect of High Latent Heat of Fusion of Ice

The specific ...

Question

The specific heat capacity of water is 4200 J/kg $^{\circ} C$ . Calculate the heat capacity of 10 kg of water per $^{\circ} C$ :

42 J

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420 J

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42 kJ

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420 kJ

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Solution

The correct option is C 42 kJ
Heat Capacity $= S p e c i f i c$ $h e a t \times m a s s$
$= 4200 J / K g^{o} C \times 10 = 42000 J = 42 k J$

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Similar questions

Calculate the heat energy required to convert completely $10 k g$ of water at $50 ° C$ into steam at $100 ° C$ , given that the specific heat capacity of water is $4200 J / (k g ° C)$ and the specific latent heat of vaporisation of water is $2260 k J / k g$ .

Q. The specific heat capacity of water is 4200 J

k g^{- 1} K^{- 1}

The amount of heat energy required to convert 1 kg of ice at $- 10^{\circ} C$ to water at $100^{\circ} C$ is 7,77,000 J. Calculate the specific latent heat of ice.

Specific heat capacity of ice = 2100 J $k g^{- 1} K^{- 1}$ , specific heat capacity of water=4200 J k $g^{- 1} K^{- 1}$ .

Q. Find the increase in mass when 1 kg of water is heated from 0

^{o}

C to

100^{o}

C. Specific heat capacity of water = 4200 J kg

^{- 1}

^{- 1}

Q. Calculate the amount of heat reqiured to convert

1 kg

of ice at

- 10^{\circ} C

into steam at

100^{\circ} C

. Specific heat capacity of ice is

= 2100 J {k g}^{- 1} K^{- 1}

, latent heat of fusion of ice

= 3.36 \times 10^{5} J {k g}^{- 1}

, specific heat capacity of water

= 4200 J {k g}^{- 1} K^{- 1}

and latent heat of vapourization of water

= 2.25 \times 10^{6} J {k g}^{- 1}

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The specific heat capacity of water is 4200 J/kg ∘C. Calculate the heat capacity of 10 kg of water per ∘C:

The correct option is C 42 kJHeat Capacity =Specific heat×mass=4200J/KgoC×10=42000J=42kJ

The specific heat capacity of water is 4200 J/kg $^{\circ} C$ . Calculate the heat capacity of 10 kg of water per $^{\circ} C$ :

The correct option is C 42 kJ
Heat Capacity $= S p e c i f i c$ $h e a t \times m a s s$
$= 4200 J / K g^{o} C \times 10 = 42000 J = 42 k J$