wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The specific heat of a substance varies with temperature t(C) as
c=0.20+0.14 t+0.023 t2 (cal/gm C) The heat required to raise the temperature of 2 gm of substance from 5 C to 15 C

A
24 calorie
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
56 calorie
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
82 calorie
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
100 calorie
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 82 calorie
Heat required to raise the temperature of m gm of substance by dT is given as
dQ=mc dTQ=mc dT
To raise the temperature of 2 gm of substance from 5 C to 15 C
Q=1552×(0.2+0.14t+0.023t2)dT=2×[0.2t+0.14t22+0.023 t33]155=82 calorie

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Calorimetry
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon