The specific heat of a substance varies with temperature t(∘C) as c=0.20+0.14t+0.023t2(cal/gm∘C) The heat required to raise the temperature of 2 gm of substance from 5∘Cto15∘C
A
24 calorie
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B
56 calorie
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C
82 calorie
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D
100 calorie
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Solution
The correct option is C 82 calorie Heat required to raise the temperature of m gm of substance by dT is given as dQ=mcdT⇒Q=∫mcdT ∴ To raise the temperature of 2 gm of substance from 5∘Cto15∘C Q=∫1552×(0.2+0.14t+0.023t2)dT=2×[0.2t+0.14t22+0.023t33]155=82calorie