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Specific Rotation

The specific ...

Question

The specific rotation of an optically active compound is constant under all conditions.

A

True

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B

False

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Solution

The correct option is B False

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Q. An optically active compound A(specific solution

100

) undergoes mutarotation in aqueous solution to form another optically active compound B(specific rotation

200

) till the specific rotation of the solution finally attains the constant value of

180

. Find Kc for the mutarotation.

Q. The optical rotation of an optically active compounds is:

Q. An organic compound having a carbon attached to four different groups is optically active. But, is the opposite also true? That is, do all optically active organic compounds have chiral carbons? Not necessarily. Presence or absence of chiral centre is not the sufficient criterion for optical activity. The ultimate criterion is the presence or absence of either plane or centre of symmetry. Two compounds which are non-superimposable mirror images of each other are called enantiomers. If a compound contains more than one chiral carbon, new words are required to describe the relationship between various stereo isomers of the compounds. Those words are diastereomers and mesomers.
The optical rotation of a solution of pure natural camphor is found to be

+ {5.76}^{o}

under the following conditions: concentration

= 0.13 g / m l

, length of polarimeter

=

1dm, wavelength

=

T = 25^{o}

C. The specific rotation of camphor is

Q. The spontaneous change in specific rotation of an opacity active compound is called ?

Q. An optically active compound

A

undergoes fist order conversion to another optically active compounds

B

C

. From the following data of optical rotation, calculate the time from the start at which the solution will become a racemic mixture.

A \to B + C

time (min)	0	10	$\infty$
optical rotation $(^{\circ})$	$15^{\circ}$	$5^{\circ}$	$- 5^{\circ}$

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