The speed of a car of mass 1000 kg is reduced from 20 m/s to 10 m/s. What is the work done by the brakes of the car?
A
150 kJ
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B
120 kJ
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C
100 kJ
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D
80 k J
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Solution
The correct option is A 150 kJ Work done by the brakes of a car will be the net change in the kinetic energy of car W=12m(v22−v12) W=12m(102−202) W=12m(100−400)=121000(−300) W=−150000J=−150KJ Hence, option A is correct.