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Work Done in Collision

The speed of ...

Question

The speed of an object of mass $2 k g$ increases from $2 m / s$ to $4 m / s$ in $3 s$ . Find out the total work done on the object during this time interval?

A

4 J

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B

6 J

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C

12 J

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D

24 J

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E

36 J

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Solution

The correct option is C $12 J$
The work done , $W =$ change in kinetic energy $= K_{f} - K_{i}$
or $W = \frac{1}{2} m v_{f}^{2} - \frac{1}{2} m v_{i}^{2} = 0.5 (2) (4^{2}) - 0.5 (2) (2^{2}) = 12 J$

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