Question

The speed of sound in mercury at a certain temperature is 1450$m/s.$ Given the density of mercury as $13.6\times {10}^{3}kg/m^3,$ the Bulk modulus formercury is

• A. $2.86\times {10}^{10}N/m^3$
• B. $3.86\times {10}^{10}N/m^3$
• C. $4.86\times {10}^{10}N/m^3$
• D. $5.86\times {10}^{10}N/m^3$

Answer 1

Answer: (A)

$2.86\times {10}^{10}N/m^3$

The velocity of the sound in relation to the bulk modulus and density is given as:

$v=\sqrt{\frac{K}{\rho }}$

$\therefore K=v^2\rho$

$K={1450}^2\times 13.6\times {10}^3$

$=2.86\times {10}^{10}N/m^3$