The speed of the particle moving along with straight line become half after every next second. The initial speed is $V_{0}$ . The total distance travelled by the particle will be

V_{0}

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2 V_{0}

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\infty

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None of the above

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Solution

The correct option is A $2 V_{0}$

Distance = $V_{0} \times 1 + \frac{V_{0}}{2} \times 1 + \frac{V_{0}}{4} \times 1 + . . . . .$

$= V_{0} \times (1 + \frac{1}{2} + \frac{1}{4} + . . . . . .) = 2 V_{0}$

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The speed of the particle moving along with straight line become half after every next second. The initial speed is V0. The total distance travelled by the particle will be

The correct option is A 2V0 Distance = V0×1+V02×1+V04×1+..... =V0×(1+12+14+......)=2V0

The speed of the particle moving along with straight line become half after every next second. The initial speed is $V_{0}$ . The total distance travelled by the particle will be

The correct option is A $2 V_{0}$

Distance = $V_{0} \times 1 + \frac{V_{0}}{2} \times 1 + \frac{V_{0}}{4} \times 1 + . . . . .$

$= V_{0} \times (1 + \frac{1}{2} + \frac{1}{4} + . . . . . .) = 2 V_{0}$