The splash of sound was heard $6$ s after dropping a stone into a well $125$ m deep. The velocity of sound is:

350

cm/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

125

m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

392

cm/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

cm/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $125$ m/s
From equation of motion we have
$s = u t + \frac{1}{2} g t^{2}$
where u= $0$ m/s;g=acceleration due to gravity= $10 m / s^{2}$ and s= distance traveled= $125$ m

Putting the above-mentioned values in the equation of motion we get

$t^{2} = \frac{250}{10}$

$t = 5 s$
Now as per question the sound of splash is after $6 s$ of dropping, thus the time taken for the sound to cover a distance of $125$ m is $1$ second.
Speed of sound $v = \frac{d i s t a n c e}{t i m e}$ = $125$ m/s

Suggest Corrections

Similar questions

Q. A stone is dropped into a well

44.1 m

deep. The splash is heard

3.13 s

after the stone is dropped. Find the velocity of sound in air. Take

g = 9.8 m / s^{2}

Q. The splash is heard

2.05 s

after the stone is dropped into a well of depth

19.6 m

. The velocity of sound is?

Q. Neha dropped a stone into a very deep well. She heard the sound only after 6.53 seconds after she dropped the stone. Find the depth of the river if the acceleration due to gravity=10m/s² and the velocity of the sound is 340m/s

A stone is dropped from a 500 m tall building into a pond. When is sound of splash heard after the dropping of the stone? g = 10 $m / s^{2}$ , speed of sound = 340 m/s

Join BYJU'S Learning Program

The splash of sound was heard 6s after dropping a stone into a well 125m deep. The velocity of sound is:

The splash of sound was heard $6$ s after dropping a stone into a well $125$ m deep. The velocity of sound is: