Question

The square root of $24025$ will have _________ digits.

Answer 1

If a perfect square has ‘$n$’ digits where n is odd, its square root has $\frac{n+1}{2}$ digits.

Number of digits in the given number = $5$ (Which is odd)

Putting the value in the formula

$\begin{array}{rcl}\frac{n+1}{2}& =& \frac{5+1}{2}\\ & =& \frac{6}{2}\\ & =& 3\end{array}$

Hence, the square root of $24025$ will have $3$ digits.