The standard deviation of 10 observations 111,211,311,...,1011 is
A
250
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B
100√3
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C
300
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D
50√33
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Solution
The correct option is D50√33 Let xi=1,2,3,...,10 Then, given observations can be written as yi=100xi+11 Standard deviation can be calculated as σ(yi)=100σ(xi) σ(xi)=√10×11×2110×6−(10×112×10)2 =√332 ⇒σ(yi)=50√33