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Question

The standard deviation of 10 observations 111,211,311,...,1011 is

A
250
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B
1003
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C
300
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D
5033
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Solution

The correct option is D 5033
Let xi=1,2,3,...,10
Then, given observations can be written as yi=100xi+11
Standard deviation can be calculated as σ(yi)=100σ(xi)
σ(xi)=10×11×2110×6(10×112×10)2
=332
σ(yi)=5033

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