The standard deviation of some temperature data in ∘C is 5. If the data were converted into ∘F, the variance would be
A
81
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B
57
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C
36
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D
25
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Solution
The correct option is A 81 We know, 0F=1.80C+32 also S.D(0C)=5 ∴S.D(0F)=S.D(1.80C+32)=1.8×S.D(0C)=1.8×5=9 (using fact [S.D(ax+b)=|a|.S.D(x)]) Hence required variance =92=81