The standard e.m.f. of the cell involving the reaction, 2Ag+(aq)+H2(g)→2Ag(s)+2H+(aq), is 0.80 V. The standard oxidation potential of Ag electrode is :
A
0.80V
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B
−0.80V
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C
0.40V
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D
0.20V
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Solution
The correct option is A−0.80V 2Ag+(aq)+H2(g)→2Ag(s)+2H+(aq),
This is reduction cell of silver ion wrt to hydrogen so for this cell,
Eocell=EoOPH+EoRPAg
0.80=0+EoRPAg+/Ag
∴EoRPAg+/Ag=0.80V so EoOPAg/Ag+=−EoRPAg+/Ag=−0.80V