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Question

The standard E.M.F of the cell written as
Cd(Hg)|CdSO4.83H2O(s)||CdSO4(sat.)|Hg2SO4(s)|Hg in which the cell reaction is
Cd(Hg)+Hg2SO4(s)+83H2O(l)CdSO4.83H2O(s)+2Hg(l) is 1.0185 V at 25oC. Calculate ΔSo for the cell reaction if (EoT)P for the cell is 5.00×105 V K1
Take, F=96485 C mol1

A
32.6 J K1
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B
12.5 kJ K1
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C
9.65 J K1
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D
8 kJ K1
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Solution

The correct option is C 9.65 J K1
The number of electrons involved in this reaction is 2. Thus, 2 faradays of electricity would be generated in the complete cell reaction.

Standard entropy change,
ΔSo=nF(EoT)P
(EoT) is temperature coefficient of cell reaction.

ΔSo=2×96485 C×5×105 V K1=9.65 J K1

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