The standard EMF of deconormal calomel electrode is 0.268 V. The EMF is:
A
−0.298V
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B
0.327V
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C
-0.327V
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D
0.298V
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Solution
The correct option is A0.327V 12Hg2Cl2+e−⟶Hg+Cl−1decinormal=10−1normal,Eo=0.268E=Eo−0.05911log[Cl−][Hg]12[Hg2Cl2]=0.268−0.05911log10−1=0.268+0.0591=0.327V