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Question

The standard EMF of deconormal calomel electrode is 0.268 V. The EMF is:

A
0.298V
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B
0.327V
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C
-0.327V
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D
0.298V
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Solution

The correct option is A 0.327V
12Hg2Cl2+eHg+Cl1decinormal=101normal,Eo=0.268E=Eo0.05911log[Cl][Hg]12[Hg2Cl2]=0.2680.05911log101=0.268+0.0591=0.327V

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