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Question

The standard heat of formation values of SF6(g) ,S(g) and F(g) are: 1100,275 and 80 KJ mol1 respectively. Then the average S - F bond energy in SF6 is:


A

301 KJ mol1

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B

183 KJ mol1

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C

309 KJ mol1

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D

280 KJ mol1

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Solution

The correct option is C

309 KJ mol1


S(g) + 6F(g) SF6(g); ΔHr = 1100 KJ mol1

S(S) S(g); ΔH = +275 KJ mol1

12 F2(g) ΔH = 80 KJ mol1

Therefore heat of formation = Bond energy of reactant - Bond energy of product - 1100 = [275 + 6 × 80] [6 × S F]

Thus bond energy of S F = 309 Kj mol1


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